x=2x^2+578

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Solution for x=2x^2+578 equation:


Simplifying
x = 2x2 + 578

Reorder the terms:
x = 578 + 2x2

Solving
x = 578 + 2x2

Solving for variable 'x'.

Reorder the terms:
-578 + x + -2x2 = 578 + 2x2 + -578 + -2x2

Reorder the terms:
-578 + x + -2x2 = 578 + -578 + 2x2 + -2x2

Combine like terms: 578 + -578 = 0
-578 + x + -2x2 = 0 + 2x2 + -2x2
-578 + x + -2x2 = 2x2 + -2x2

Combine like terms: 2x2 + -2x2 = 0
-578 + x + -2x2 = 0

Begin completing the square.  Divide all terms by
-2 the coefficient of the squared term: 

Divide each side by '-2'.
289 + -0.5x + x2 = 0

Move the constant term to the right:

Add '-289' to each side of the equation.
289 + -0.5x + -289 + x2 = 0 + -289

Reorder the terms:
289 + -289 + -0.5x + x2 = 0 + -289

Combine like terms: 289 + -289 = 0
0 + -0.5x + x2 = 0 + -289
-0.5x + x2 = 0 + -289

Combine like terms: 0 + -289 = -289
-0.5x + x2 = -289

The x term is x.  Take half its coefficient (0.5).
Square it (0.25) and add it to both sides.

Add '0.25' to each side of the equation.
-0.5x + 0.25 + x2 = -289 + 0.25

Reorder the terms:
0.25 + -0.5x + x2 = -289 + 0.25

Combine like terms: -289 + 0.25 = -288.75
0.25 + -0.5x + x2 = -288.75

Factor a perfect square on the left side:
(x + 0.5)(x + 0.5) = -288.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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